Print alphabet pattern ‘l’¶
Print alphabet pattern ‘l’.
Expected output:
0123456
0 *
1 *
2 *
3 *
4 *
5 *
6 *****
result_str=""
for row in range(0, 7):
for column in range(0, 7):
if (column == 1 or
(row == 6 and column != 0 and column < 6)
):
result_str += "*"
else:
result_str += " "
result_str += "\n"
print(result_str)
Output:
*
*
*
*
*
*